document.write( "Question 253244: The perimeter of a rectangle is 48 inches. The width of the rectangle is 2 more than half the length.
\n" ); document.write( " . Write a system of linear equations to model this
\n" ); document.write( " . Name the method you would use to solve system you wrote above
\n" ); document.write( " . Use the method you stated above to solve the system for the length and width of the rectangle stated above
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Algebra.Com's Answer #185573 by Greenfinch(383)\"\" \"About 
You can put this solution on YOUR website!
Call width X and length Y
\n" ); document.write( "Perimeter is 2X + 2Y = 48
\n" ); document.write( "Relation is X-2 = Y/2 or 2X - Y = 4\r
\n" ); document.write( "\n" ); document.write( "You can solve by elimination
\n" ); document.write( "Take Equation 2 from equation 1 and get 3Y = 44 (Y = 14 2/3)
\n" ); document.write( "Substitute in equation 1 and get X = (48 - 2x(14 2/3))2 = 9 1/3
\n" ); document.write( "Check in equation 2 X - 2 = 7 1/3 Y/2 = 7 1/3 CHECKS\r
\n" ); document.write( "\n" ); document.write( "you can solve by substitution
\n" ); document.write( "from equation 1 X = 24 - Y
\n" ); document.write( "so in equation 2 (24 - Y) - 2 = Y/2
\n" ); document.write( "22 = 3/2 Y
\n" ); document.write( "y = 2/3 x 22 = 14 2/3\r
\n" ); document.write( "\n" ); document.write( "Amazing, it works both ways !!
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