document.write( "Question 253285: The tens-digit of a three digit number is 3 less than 5 times the units digit. Three times the sum of the digits is 2 more than 4 times the hundreds digit. If the digits are reversed, the new number is 594 less than the original number. Find the original number. (find a system of 3 equations then use the system to find the original number). \n" ); document.write( "
Algebra.Com's Answer #185572 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
Why do we need three equations? We need three equations because we will have three unknowns. We need one equation for each unknown.
\n" ); document.write( "Let the digits be h, t and u
\n" ); document.write( "Let the number be 100h+10t+u
\n" ); document.write( "t=5u-3
\n" ); document.write( "3*(h+t+u)=2+4h
\n" ); document.write( "100u+10t+h+594=100h+10t+u
\n" ); document.write( "721
\n" ); document.write( "h=7
\n" ); document.write( "t=2
\n" ); document.write( "u=1
\n" ); document.write( "check
\n" ); document.write( "2=5*1-3
\n" ); document.write( "2=5-3=2 ok
\n" ); document.write( "3*(7+2+1)=2+4*7
\n" ); document.write( "3*10=2+28
\n" ); document.write( "30=30 ok
\n" ); document.write( "127+594=721
\n" ); document.write( "721=721 ok \n" ); document.write( "
\n" );