document.write( "Question 253285: The tens-digit of a three digit number is 3 less than 5 times the units digit. Three times the sum of the digits is 2 more than 4 times the hundreds digit. If the digits are reversed, the new number is 594 less than the original number. Find the original number. (find a system of 3 equations then use the system to find the original number). \n" ); document.write( "
Algebra.Com's Answer #185571 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"h\" = hundreds digit
\n" ); document.write( "Let \"t\" = tens digit
\n" ); document.write( "Let \"u\" = units digit
\n" ); document.write( "The actual number must be
\n" ); document.write( "\"100h+%2B+10t+%2B+u\"
\n" ); document.write( "given:
\n" ); document.write( "(1)\"t+=+5u+-+3\"
\n" ); document.write( "(2) \"3%2A%28h+%2B+t+%2B+u%29+=+4h+%2B+2\"
\n" ); document.write( "The number with the digits reversed would be
\n" ); document.write( "\"100u+%2B+10t+%2B+h\"
\n" ); document.write( "(3) \"100u+%2B+10t+%2B+h+=+100h+%2B+10t+%2B+u+-+594\"
\n" ); document.write( "-------------------------------------
\n" ); document.write( "I have the 3 equations and I just need to tidy them up
\n" ); document.write( "and solve for \"h\",\"t\", and \"u\"
\n" ); document.write( "I'll leave this for you
\n" ); document.write( "
\n" );