document.write( "Question 31992This question is from textbook Algebra1
\n" ); document.write( ": How do you factor trinomials that are equal to something such as:x^2-x+56=17x
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Algebra.Com's Answer #18556 by Earlsdon(6294)\"\" \"About 
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Well, first, you need to get you quadratic equation into the standard form \"ax%5E2+%2B+bx+%2B+c+=+0\". So you'll need to get everything on one side of the = sign.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x%2B56+=+17x\" Subtract 17x from both sides of the equation.
\n" ); document.write( "\"x%5E2+-+x+%2B+56+-+17x+=+0\" Simplify.
\n" ); document.write( "\"x%5E2+-+18x+%2B+56+=+0\" Now you can factor the equation.
\n" ); document.write( "\"x+-+4%29%28x+-+14%29+=+0\" Apply the zero products principle if you want to solve for x.
\n" ); document.write( "\"x-4+=+0\" and/or \"x+-+14+=+0\"
\n" ); document.write( "If \"x+-+4+=+0\" then \"x+=+4\"
\n" ); document.write( "If \"x+-+14+=+0\" then \"x+=+14\"
\n" ); document.write( "The roots are:
\n" ); document.write( "x = 4
\n" ); document.write( "x = 14
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