document.write( "Question 253271: Hi i need help in this question, Car A is traveling on highway 10 at an average speed of 70 miles per hour. Car B is traveling on highway 75 at an average speed of 55 miles per hour. How many more feet per second dose Car A travel than Car B. \n" ); document.write( "
Algebra.Com's Answer #185550 by JimboP1977(311)\"\" \"About 
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Well to go from miles per hour to feet per second we need to know how many feet there are in a mile and how many seconds there are in an hour. There are 5280 feet in 1 mile and 3600 seconds (1hour times 60 minutes times 60 seconds) in 1 hour.\r
\n" ); document.write( "\n" ); document.write( "70 miles per hour mean that the Car A is travelling 70*5280 feet per hour. which is 369600 feet per hour. We want to know the how many feet the Car A travels per second. So we divide 369600 by 3600 to give 102 and 2/3 feet per seond.\r
\n" ); document.write( "\n" ); document.write( "We do the same for Car B. 55*5280/3600=80 and 2/3 feet per second. \r
\n" ); document.write( "\n" ); document.write( "So the difference between the two cars is 102 and 2/3 feet per second minus 80 2/3 feet per second which is 22 feet per second.
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