document.write( "Question 32042: A customer has asked a caterer for 60LB of nuts, 60% of which are to be cashews. The caterer has available mixtures of 70% cashews and 45% cashews. How many pounds of each mixture should be used? \n" ); document.write( "
Algebra.Com's Answer #18555 by Earlsdon(6294)\"\" \"About 
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The caterer needs to mix x lbs of the 70% cashew mixture with (60-x) lbs of the 45% cashew mixture to obtain the 60 lbs of 60% cashew mixture. Change the percentages to their decimal equivalents and write the algebraic equation to solve for x.
\n" ); document.write( "\"x%280.7%29+%2B+%2860-x%29%280.45%29+=+60%280.6%29\" Simplify and solve for x.
\n" ); document.write( "\"0.7x+%2B+27+-+0.45x+=+36\" Combine like-terms.
\n" ); document.write( "\"0.25x+%2B+27+=+36\" Subtract 27 from both sides.
\n" ); document.write( "\"0.25x+=+9\" Divide both sides by 0.25
\n" ); document.write( "\"x+=+36\"\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "The caterer should mix 36 lbs of the 70% cashew mixture with (60-36 = 24) lbs of the 45% cashew mixture to obtain 60 lbs of 60% cashew mixture.
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