document.write( "Question 32041: I would have tried to answer this question if I knew where to start.\r
\n" ); document.write( "\n" ); document.write( "Marvelous Marilyn wants to combine a 30% alcohol solution with a 50% alcohol solution to get 500 mg of an 80% alcohol solution. Please help her accomplish this task.\r
\n" ); document.write( "\n" ); document.write( "Please help!
\n" ); document.write( "Shakema \n" ); document.write( "
Algebra.Com's Answer #18553 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, unless Marvelous Marilyn is also a magician, there is no way for her to obtain a solution of 80% alcohol from a mixture of two alcohol solutions of lesser concentration.
\n" ); document.write( "If you give it a little thought, you will see that by mixing a 30% solution with a 50% solution, you can never get a solution that is greater than 50%. Indeed, you will dilute the 50% solution by adding the 30% solution, so you will end up with something in between 30% and 50%. Anyway, just to show you, algebraically, let x = the amount of 30% alcohol solution you will need:
\n" ); document.write( "\"x%280.3%29+%2B+%28500-x%29%280.5%29+=+500%280.8%29\" Simplify and solve for x.
\n" ); document.write( "\"0.3x+%2B+250+-+0.5x+=+400\"
\n" ); document.write( "\"-0.2x+%2B+250+=+400\" Subtract 250 from both sides.
\n" ); document.write( "\"-0.2x+=+150\" Divide both sides by -0.2
\n" ); document.write( "\"x+=+-750\"\r
\n" ); document.write( "\n" ); document.write( "So, you would need -750 mg of 30% alcohol solution and -250 mg of 50% alcohol solution. Doesn't make sense, does it?
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