document.write( "Question 253245: I am trying to solve these equations. We are to graph the system and estimate the solution then check the solution algebraically:
\n" ); document.write( "2x-3y = -2
\n" ); document.write( "x+y = -6\r
\n" ); document.write( "\n" ); document.write( "This is what I have done so far and it isn't coming out correctly:
\n" ); document.write( "2x-3y = -2
\n" ); document.write( "2x+2=3y
\n" ); document.write( "2/3x + 2/3 = y\r
\n" ); document.write( "\n" ); document.write( "x+y= -6
\n" ); document.write( "x+6= -y\r
\n" ); document.write( "\n" ); document.write( "I plotted the line at (0,2/3) (3, 2 2/3) and at (-3, -1 1/3)\r
\n" ); document.write( "\n" ); document.write( "The book says I am wrong and I don't understand why. Please help!\r
\n" ); document.write( "\n" ); document.write( "ANy help you can give would be greatly appreciated. Thank you.
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Algebra.Com's Answer #185523 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First let's graph \"2x-3y+=+-2\". To do so, we need to solve for 'y'\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3y=-2\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-3y=-2-2x\" Subtract \"2x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-3y=-2x-2\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2x-2%29%2F%28-3%29\" Divide both sides by \"-3\" to isolate y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%28-2%29%2F%28-3%29%29x%2B%28-2%29%2F%28-3%29\" Break up the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%282%2F3%29x%2B2%2F3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Now in order to graph \"y=%282%2F3%29x%2B2%2F3\", we need two points. \r
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\n" ); document.write( "\n" ); document.write( "Take note that when \"x=2\", then \"y=%282%2F3%29%282%29%2B2%2F3=4%2F3%2B2%2F3=6%2F3=2\". So we have one point (2,2). \r
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\n" ); document.write( "\n" ); document.write( "Also, when \"x=5\", \"y=%282%2F3%29%285%29%2B2%2F3=10%2F3%2B2%2F3=12%2F3=4\" giving us another point (5,4). Plot these points to get\r
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\n" ); document.write( "\n" ); document.write( "Now draw a straight line through the two points. This line is the graph of \"y=%282%2F3%29x%2B2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Graph of \"y=%282%2F3%29x%2B2%2F3\" through the two points (2,2) and (5,4)\r
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\n" ); document.write( "\n" ); document.write( "Now let's graph \"x%2By+=+-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=-6\" Start with the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-6-x\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x-6\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"y=-x-6\" we can see that the equation is in slope-intercept form \"y=mx%2Bb\" where the slope is \"m=-1\" and the y-intercept is \"b=-6\" \r
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\n" ); document.write( "\n" ); document.write( "Since \"b=-6\" this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis\r
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\n" ); document.write( "\n" ); document.write( "So we have one point \r
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\n" ); document.write( "\n" ); document.write( "Now since the slope is comprised of the \"rise\" over the \"run\" this means\r
\n" ); document.write( "\n" ); document.write( "\"slope=rise%2Frun\"\r
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\n" ); document.write( "\n" ); document.write( "Also, because the slope is \"-1\", this means:\r
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\n" ); document.write( "\n" ); document.write( "\"rise%2Frun=-1%2F1\"\r
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\n" ); document.write( "\n" ); document.write( "which shows us that the rise is -1 and the run is 1. This means that to go from point to point, we can go down 1 and over 1\r
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\n" ); document.write( "\n" ); document.write( "So starting at , go down 1 unit \r
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\n" ); document.write( "\n" ); document.write( "and to the right 1 unit to get to the next point \r
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\n" ); document.write( "\n" ); document.write( "Now draw a line through these points to graph \"y=-x-6\"\r
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\n" ); document.write( "\n" ); document.write( "So this is the graph of \"y=-x-6\" through the points and \r
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\n" ); document.write( "\n" ); document.write( "Now let's graph the two equations on the same coordinate plane\r
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\n" ); document.write( "\n" ); document.write( "Graph of \"y=%282%2F3%29x%2B2%2F3\" (red) and \"y=-x-6\" (green)\r
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\n" ); document.write( "\n" ); document.write( "From the graph, we see that the two lines intersect at the point (-4, -2). So the solutions are \"x=-4\" and \"y=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3y=-2\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28-4%29-3%28-2%29=-2\" Plug in \"x=-4\" and \"y=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"-8%2B6=-2\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"-2=-2\" Add. Since the equation is true, this verifies our answer on the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=-6\" Move onto the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-4-2=-6\" Plug in \"x=-4\" and \"y=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"-6=-6\" Subtract. Since the equation is true, this verifies our answer for the second equation.\r
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\n" ); document.write( "\n" ); document.write( "Since the values \"x=-4\" and \"y=-2\" satisfy both equations, this verifies our answer completely.
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