document.write( "Question 253220: the width of a rectangle is 5 meters less than its length. the area is 84 square meters. find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #185468 by richwmiller(17219)\"\" \"About 
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\n" ); document.write( "Area=L*W
\n" ); document.write( "W=L-5
\n" ); document.write( "substitute L-5 for W
\n" ); document.write( "84=L*(L-5)
\n" ); document.write( "84=L^2-5L
\n" ); document.write( "L^2-5L-84=0
\n" ); document.write( "we ant factors of 84 with a difference of 5
\n" ); document.write( "1,84
\n" ); document.write( "2,42=6*7=3*2*7
\n" ); document.write( "3,14
\n" ); document.write( "4,21
\n" ); document.write( "6,14
\n" ); document.write( "7,12\r
\n" ); document.write( "\n" ); document.write( "7 and 12 will do
\n" ); document.write( "We want the larger number to be negative
\n" ); document.write( "(L-12)(L+7)=0
\n" ); document.write( "L=12 since a rectangle can't have a negative size of 7\r
\n" ); document.write( "\n" ); document.write( "W=L-5=7
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