document.write( "Question 253197: How do you find the area of an isosceles trapezoid with legs = 10, shorter base = 10 and base angles = 60 degrees? \n" ); document.write( "

Algebra.Com's Answer #185463 by drk(1908) $\"\"$ $\"About$

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First, draw an isosceles trapezoid with the question information included.
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\n" ); document.write( "Second, draw an altitude from the top vertex on the left to the bottom, long base, and then do the same on the right top vertex. We have created 2 right (30-60-90) triangles. The height becomes 5sqrt(3) and the long base will become 20; remember that the side opposite the 30 degree angle is 1/2 the hypotenuse of 10 = 5.
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\n" ); document.write( "Third find the area as
\n" ); document.write( " $\"A+=%281%2F2%29%2A%2810%2B20%29%2A5%2Asqrt%283%29\"$
\n" ); document.write( " $\"A+=+75sqrt%283%29\"$ \n" ); document.write( "

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