document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253168>Question 253168</A>: <I><SPAN STYLE=\"word-break: break-all;\">                                         AB<BR>\n" );
document.write( "                                       +BA<BR>\n" );
document.write( "                                     ______<BR>\n" );
document.write( "                                       CD4<BR>\n" );
document.write( "In the correctly worked addition problem above, each letter represents a different nonzero digit. What is one possible value of the two-digit number represented above as AB ?\r<BR>\n" );
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document.write( "(A) 74       (B) 31       (C) 86           (D) 47         (E) 95<BR>\n" );
document.write( "option: (c)86<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185462 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We know the sum must end in 4<BR>\n" );
document.write( "74+47 ends in 1<BR>\n" );
document.write( "31+13 ends in 4 but has only two digits<BR>\n" );
document.write( "86+68 ends in 4 and has three digits sum is 154<BR>\n" );
document.write( "47+74 ends in 1 same as A)<BR>\n" );
document.write( "95+59 ends in 4 and has three digits sum is 154<BR>\n" );
document.write( "A,B, C and D are all unique so 95 and 59 can't use the 5 again in the sum<BR>\n" );
document.write( "So the only acceptable answer is 86 and 68. \r<BR>\n" );
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