document.write( "Question 253210: Another word problem!\r
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document.write( "A six passenger plan cruises at 180 mph in calm air. If the plane flies 7 miles with the wind in the same amount of time as it flies 5 miles against the wind, then what is the wind speed? \n" );
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Algebra.Com's Answer #185452 by drk(1908) ![]() You can put this solution on YOUR website! This is a rate x time = distance problem. Here is the table based on the question: \n" ); document.write( "wind . . . . . rate . . . . . . . . . time . . . . . . . . . . .distance \n" ); document.write( "with . . . . . r + 180 . . . . . . . t . . . . . . . . . . . . . . 7 \n" ); document.write( "against . . . r - 180 . . . . . . . . t . . . . . . . . . . . . . . 5 \n" ); document.write( "The time is distance / rate or \n" ); document.write( "7/(r+180) and 5/(r-180). \n" ); document.write( "Since the times were the same set these fractions equal to each other as: \n" ); document.write( "7/(r+180) = 5/(r-180). \n" ); document.write( "Cross multiply to get \n" ); document.write( "7r - 1260 = 5r + 900 \n" ); document.write( "solve for r to get \n" ); document.write( "2r = 2160 \n" ); document.write( "r = 1080. \n" ); document.write( "The wind speed is 1080 mph. \n" ); document.write( " \n" ); document.write( " |