document.write( "Question 32012This question is from textbook
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Algebra.Com's Answer #18545 by Paul(988) $\"\"$ $\"About$

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Let the ten digit number be x
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Let the one digit number be y
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document.write( "x+y=5
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document.write( "y=5-x (subsitution)
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document.write( "WHen the digit is reversed:
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document.write( "10y+x=10x+y+9
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document.write( "Subsitute for y:
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document.write( "10(5-x)+x=10x+5-x+9
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document.write( "50-10x+x=10x+14-x
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document.write( "50-9x=9x+14
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document.write( "18x=36
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document.write( "x=2
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document.write( "y=5-2
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document.write( "y=3
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document.write( "Hence, the 10 digit number is 2 and the one digit number is 3.
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document.write( "The number is 23.
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document.write( "Paul. \n" );
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