document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32038>Question 32038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 1 cm longer than its width.  if the diagonal of the rectangle is 4c, what are the demensions (l and w) of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18541 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET WIDTH =B<BR>\n" );
document.write( "LENGTH =B+1<BR>\n" );
document.write( "DIAGONAL =SQRT (L^2+B^2)=SQRT(B^2+(B+1)^2)=5...IS IT 4 OR 4C ?I AM TAKING IT AS 5<BR>\n" );
document.write( "TO SHOW YOU THE METHOD.....SQUARING<BR>\n" );
document.write( "B^2+B^2+2B+1=25<BR>\n" );
document.write( "2B^2+2B-24=0<BR>\n" );
document.write( "B^2+B-12=0<BR>\n" );
document.write( "B^2+4B-3B-12=0<BR>\n" );
document.write( "B(B+4)-3(B+4)=0<BR>\n" );
document.write( "(B+4)(B-3)=0<BR>\n" );
document.write( "B=3<BR>\n" );
document.write( "L=4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );