document.write( "Question 253132: Determine the quadratic equation whose roots have a sum of 12 and the roots difference is 4i. (Write a let statement to identify your roots) \n" ); document.write( "
Algebra.Com's Answer #185395 by MathTherapy(10552)\"\" \"About 
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To find any quadratic equation of the form \"ax%5E2+%2B+bx+%2B+c+=+0\", we have to realize that:\r
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\n" ); document.write( "\n" ); document.write( "a = 1 (always)
\n" ); document.write( "b = - (sum of roots)
\n" ); document.write( "c = product of roots\r
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\n" ); document.write( "\n" ); document.write( "Since a is always 1, and the sum of the roots = 12, then b = - (12) = -12\r
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\n" ); document.write( "\n" ); document.write( "We now have: \"x%5E2+-+12x+%2B+c+=+0\" \r
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\n" ); document.write( "\n" ); document.write( "To find c, we need to 1st determine the roots and multiply them\r
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\n" ); document.write( "\n" ); document.write( "Let root 1 be \"r%5B1%5D\", and root 2, \"r%5B2%5D\"\r
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\n" ); document.write( "\n" ); document.write( "Since the sum of the roots = 12, then ----- \"r%5B1%5D+%2B+r%5B2%5D+=+12\" --------- eq (i)
\n" ); document.write( "Also, since the roots’ difference = 4i, then \"r%5B1%5D+-+r%5B2%5D+=+4i\" --------- eq (ii)\r
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\n" ); document.write( "\n" ); document.write( "Adding equations (i) & (ii), we get: \"2r%5B1%5D+=+12+%2B+4i\" \r
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\n" ); document.write( "\n" ); document.write( "\"r%5B1%5D+=+%2812+%2B+4i%29%2F2\" or \"r%5B1%5D+=+6+%2B+2i\" \r
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\n" ); document.write( "\n" ); document.write( "Substituting 6 + 2i for \"r%5B1%5D\" in eq (i), we get: \"6+%2B+2i+%2B+r%5B2%5D+=+12\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5B2%5D+=+12+-+6+-+2i\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5B2%5D+=+6+-+2i\" \r
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\n" ); document.write( "\n" ); document.write( "Since we now have both roots, \"r%5B1%5D+=+6+%2B+2i\" and \"r%5B2%5D+=+6+-+2i\", we multiply these two roots to get “c.”\r
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\n" ); document.write( "\n" ); document.write( "Therefore, “c” = (6 + 2i)(6 – 2i) = \"36+-+4i%5E2\", or, 36 – 4(-1) = 40\r
\n" ); document.write( "\n" ); document.write( "With “a” being 1, “b” being – 12, and “c” being 40, the quadratic equation in the form \"ax%5E2+%2B+bx+%2B+c+=+0\" = \"highlight_green%28x%5E2+-+12x+%2B+40+=+0%29\"
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