document.write( "Question 32016: 4x2 = 35 - 4x\r
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Algebra.Com's Answer #18539 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! 4x2 = 35 - 4x\r\n" ); document.write( "\r\n" ); document.write( "Add 4x to, and subtract 35 from, both sides to get 0 on the right\r\n" ); document.write( "\r\n" ); document.write( " 4x2 + 4x - 35 = 0 \r\n" ); document.write( "\r\n" ); document.write( "Factor the left side:\r\n" ); document.write( "\r\n" ); document.write( " (2x + 7)(2x - 5) = 0\r\n" ); document.write( "\r\n" ); document.write( "Use the 0-factor principle. Set each factor on the left = 0.\r\n" ); document.write( "\r\n" ); document.write( "Setting 2x + 7 = 0\r\n" ); document.write( "\r\n" ); document.write( " 2x = -7\r\n" ); document.write( "\r\n" ); document.write( " x = -7/2\r\n" ); document.write( "\r\n" ); document.write( "Setting 2x - 5 = 0\r\n" ); document.write( "\r\n" ); document.write( " 2x = 5\r\n" ); document.write( "\r\n" ); document.write( " x = 5/2\r\n" ); document.write( "\r\n" ); document.write( "There are two solutions, -7/2 and 5/2\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r\n" ); document.write( "AnlytcPhil@aol.com\n" ); document.write( " |