document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250239>Question 250239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> change the fraction w-3 over w+5 into an equivalent fraction with the denominator w^2+w-20 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185382 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (W-3)/(W+5) is the start. The denominator is changed to W^2 + W -20<BR>\n" );
document.write( "This factorises to (W + 5)(W - 4), so we need to multiply the numerator by (W -4)<BR>\n" );
document.write( "as well.<BR>\n" );
document.write( "(w - 3)(w - 4)= w^2 -7w + 12<BR>\n" );
document.write( "So equivalent is (W^2 - 7W + 12)/(W^2 + W - 20) </SPAN>\n" );
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