document.write( "Question 253112: How would I graph m=-1/3;b=3 ? \n" ); document.write( "
Algebra.Com's Answer #185339 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Since m=-1/3;b=3, you have the equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Looking at \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have one point \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now since the slope is comprised of the \"rise\" over the \"run\" this means\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, because the slope is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "which shows us that the rise is -1 and the run is 3. This means that to go from point to point, we can go down 1 and over 3\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So starting at \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and to the right 3 units to get to the next point \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now draw a line through these points to graph \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check out this solver for more help on graphing. \n" ); document.write( " |