document.write( "Question 32008: sorry i don't have a book its on my computer...but the question is solve the following inequality for x. 19x^2+24x+1<0 \n" ); document.write( "

Algebra.Com's Answer #18533 by venugopalramana(3286) $\"\"$ $\"About$

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19x^2+24x+1<0
\n" ); document.write( "solve 19x^2+24x+1=0 using quadratic formula..let the 2 roots be a and b in increasing order.
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( " $\"x+=+%28-24+%2B-+sqrt%28+24%5E2-4%2A19%2A1+%29%29%2F%282%2A19%29+\"$
\n" ); document.write( " $\"x+=+%28-24+%2B-+sqrt%28+576-76+%29%29%2F%2838%29+\"$
\n" ); document.write( " $\"x+=+%28-24+%2B-+10%2Asqrt%285%29%29%2F38+%29\"$
\n" ); document.write( " $\"x+=+%28-24+%2B+10%2Asqrt%285%29%29%2F38+%29\"$ =b
\n" ); document.write( " $\"x+=+%28-24+-+10%2Asqrt%285%29%29%2F38+%29\"$ =a
\n" ); document.write( "call the 2 roots a and b
\n" ); document.write( "now then this can be written as (x-a)(x-b)=0
\n" ); document.write( "if this product has to be not equal to 0 but less than zero,
\n" ); document.write( "then x should lie between a and b.,since then while one factor is positive the other would be negative and the product would be negative.
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