document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253040>Question 253040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 400g solution made up of 40% sugar must be added to a 2oog solution. What should be the percentage of sugar in 200g of solution in order to produce a 38% sugar solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185246 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     A 400g solution made up of 40% sugar must be added to a 2oog solution. What should be the percentage of sugar in 200g of solution in order to produce a 38% sugar solution?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = percentage of sugar in 200g solution<BR>\n" );
document.write( "then<BR>\n" );
document.write( "200x + .40(400) = .38(400+200)<BR>\n" );
document.write( "200x + .40(400) = .38(600)<BR>\n" );
document.write( "200x + 160 = 228<BR>\n" );
document.write( "200x = 228-160<BR>\n" );
document.write( "200x = 68<BR>\n" );
document.write( "x = .34<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x = 34%\r<BR>\n" );
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document.write( " </SPAN>\n" );
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