document.write( "Question 253036: A three- digit number divisible by 5 has a hundreds digit that is 2 more than the tens digit. If the number is 43 times the sum of the digit, what is the number? \n" ); document.write( "
Algebra.Com's Answer #185221 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! let a= the number \n" ); document.write( "100x+10y+z=a \n" ); document.write( "x=y+2 \n" ); document.write( "a=43*(x+y+z) \n" ); document.write( "we also know that z=0 or z=5 since the number is divisible by 5 \n" ); document.write( "So we plug in 5 or 0 to test it. which ever gives us three integers for x, y and a is the right choice for z \n" ); document.write( "hint z=5 works \n" ); document.write( " \n" ); document.write( " |