document.write( "Question 252992: A truck traveling at a constant rate of 45 miles per hour leaves Albany. One hour later a car traveling at a constant rate of 60 miles per hour also leaves Albany traveling in the same direction on the same highway. How long will it take for the car to catch up to the truck, if both vehicles continue in the same direction on the highway? \n" ); document.write( "
Algebra.Com's Answer #185196 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let t=time that elapses before the car catches the truck(after the car leaves)
\n" ); document.write( "When the car leaves, the truck has travelled 45*1=45 mi\r
\n" ); document.write( "\n" ); document.write( "Total distance truck travels in t hours=45+45t
\n" ); document.write( "Total distance car travels in t hours=60t\r
\n" ); document.write( "\n" ); document.write( "When the above two distances are equal, the car will have caught up with the truck,so:
\n" ); document.write( "45+45t=60t subtract 45t from each side
\n" ); document.write( "45+45t-45t=60-45t collect like terms
\n" ); document.write( "45=15t
\n" ); document.write( "t=3 hours-------------------------ans
\n" ); document.write( "CK
\n" ); document.write( "distance truck travels:
\n" ); document.write( "45+3*45=180 mi
\n" ); document.write( "Distance car travels=3*60=180 mi\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "
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