document.write( "Question 252978: an airplane flew for 4.23 hours with a 25.5km/h tail wind. the return flight against the same tail wind took 4.97 hours. find the speed of the plane in still air. \n" ); document.write( "
Algebra.Com's Answer #185173 by Greenfinch(383)\"\" \"About 
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Speed of aircraft is X
\n" ); document.write( "On outward trip (X + 25.5) = 4.23/Distance
\n" ); document.write( "On inbound trip (X - 25.5) = 4.97/Distance
\n" ); document.write( "Equating the distances
\n" ); document.write( " Distance = (X + 25.5)/4.97 = (X - 25.5)/4.23
\n" ); document.write( "So 4.23(X + 25.5) = 4.97(X - 25.5)\r
\n" ); document.write( "\n" ); document.write( "4.23X + 107.865 = 4.97X - 126.735\r
\n" ); document.write( "\n" ); document.write( "234.6 = 0.74 X
\n" ); document.write( "X= 317.027 km/hr\r
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