document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31977>Question 31977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How can i solve this by using the substitution method?\r<BR>\n" );
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document.write( "x=(1/5)y<BR>\n" );
document.write( "3x+2y=26 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18516 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 1st equation tell you what \"x\" is.<BR>\n" );
document.write( "Substitute that value of \"x\" into the 2nd equation to get:<BR>\n" );
document.write( "3((1/5)y)+2y=26<BR>\n" );
document.write( "(3/5)y+2y=26<BR>\n" );
document.write( "(13/5)y=26<BR>\n" );
document.write( "(1/5)y=2<BR>\n" );
document.write( "y=10<BR>\n" );
document.write( "Substitute that back into the 1st equation to find \"x\".<BR>\n" );
document.write( "x=(1/5)y<BR>\n" );
document.write( "x=(1/5)(10)<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "Solution x=2 and y=10<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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