document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250300>Question 250300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right circular cylinder has a surface area of 112&#960;.  If the height of the cylinder is 10 find the radius of its base. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185148 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Surface area is top and bottom  2 x r^2 x pi<BR>\n" );
document.write( "side is 2 x r x h x pi<BR>\n" );
document.write( "We are told that the area is 112 x pi<BR>\n" );
document.write( "so we can remove pi from the question and get<BR>\n" );
document.write( "(2 x r^2) + (2 x r x h) = 112<BR>\n" );
document.write( "and since h = 10 and there are factors of 2 on both sides<BR>\n" );
document.write( "r^2 + 10 x r = 56<BR>\n" );
document.write( "0r r^2 + 10 x r - 56 = 0<BR>\n" );
document.write( "or (r - 4)(r + 14) = 0<BR>\n" );
document.write( "r = 4 or -14<BR>\n" );
document.write( "As -14 isn't an option, r = 4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );