document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250317>Question 250317</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use inductive reasoning to describe the pattern. Then find the next two numbers in each pattern. 3, 3.3, 3.63, 3.993,... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185140 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185140\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here is our set of numbers: 3, 3.3, 3.63, 3.993,...<BR>\n" );
document.write( "we can't add or subtract to go from one term to the next, so we have to use multiplication or division. We will use common ratios to find our multiplier.<BR>\n" );
document.write( "t2 / t1 = 3.3 /3 = 1.1<BR>\n" );
document.write( "t3 / t2 = 3.63 / 3.3 = 1.1<BR>\n" );
document.write( "t4 / t3 = 3.993 / 3.63 = 1.1.<BR>\n" );
document.write( "I now know we have an infinite geometric series.<BR>\n" );
document.write( "The pattern is multiply each term by 1.1 to get the next term.<BR>\n" );
document.write( "t5 = 3.993 * 1.1 = 4.3923<BR>\n" );
document.write( "t6 = 4.3923 * 1.1 = 4.83153 </SPAN>\n" );
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