document.write( "Question 31967This question is from textbook Intermedate Algebra
\n" ); document.write( ": Solve for x\r
\n" ); document.write( "\n" ); document.write( "x^3 + 3x^2 - 4x - 12 = 0 \n" ); document.write( "

Algebra.Com's Answer #18513 by stanbon(75887) $\"\"$ $\"About$

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x^2(x+3)-4(x+3)=0
\n" ); document.write( "(x+3)(x^2-4)=0
\n" ); document.write( "(x+3)(x-2)(x+2)=0
\n" ); document.write( "x=-3 or x=2 or x=-2
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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