document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250431>Question 250431</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A landscaper wants to put a cement walk with uniform width around a garden that measures 20x40 feet,  She has enough cement to cover 660 ft squared.  How wide should it be to us all the cement?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185089 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 20*40+660=(20+x)(40+x)<BR>\n" );
document.write( "800+660=800+60x+x^2<BR>\n" );
document.write( "x^2+60x-660=0<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "x=(-60+_sqrt[60^2-4*1*-660])/2*1<BR>\n" );
document.write( "x=(-60+-sqrt[3600+2640])/2<BR>\n" );
document.write( "x=(-60+-sqrt6240)/2<BR>\n" );
document.write( "x=(-60+-78.99)/2<BR>\n" );
document.write( "x=(-60+78.99)/2<BR>\n" );
document.write( "x=19.99/2<BR>\n" );
document.write( "x=9.497 ans. for the width of the cement walk.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "20*40+660=(20+9.497)(40+9.497)<BR>\n" );
document.write( "800+660=29.497*49.497<BR>\n" );
document.write( "1460~1460  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );