document.write( "Question 250461: Originally the dimensions of a rectangle were 20 cm by 23 cm. When both dimensions were decreased by the same amount, the area of the rectangle decreased by 120 cm (squared). Find the dimensions of the new rectangle. \n" ); document.write( "
Algebra.Com's Answer #185083 by checkley77(12844)\"\" \"About 
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(20-x)(23-x)=20*23-120
\n" ); document.write( "460-43x+x^2=460-120
\n" ); document.write( "x^2-43x+460-460+120=0
\n" ); document.write( "x^2-43x+120=0
\n" ); document.write( "(x-40)(x-3)=0
\n" ); document.write( "x-3=0
\n" ); document.write( "x=3 cm. is the decrease in size of both sides.
\n" ); document.write( "Proof:
\n" ); document.write( "(20-3)(23-3)=20*23-120
\n" ); document.write( "17*20=460-120
\n" ); document.write( "340=340
\n" ); document.write( "
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