document.write( "Question 252926: divide and simplify so that there are no radicals in the denominator. show your steps.\r
\n" ); document.write( "\n" ); document.write( "1. square root 7 over 100\r
\n" ); document.write( "\n" ); document.write( "2. square root of 18 + square root 24 over square root of 6\r
\n" ); document.write( "\n" ); document.write( "3. 8 over square root of 6\r
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Algebra.Com's Answer #185056 by dabanfield(803)\"\" \"About 
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divide and simplify ao that there are no radicals in the denominator. show your steps.
\n" ); document.write( "1. square root 7 over 100
\n" ); document.write( "2. square root of 18 + square root 24 over square root of 6
\n" ); document.write( "3. 8 over square root of 6 \r
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\n" ); document.write( "\n" ); document.write( "(1.) sqrt(7/100) = sqrt(7)/sqrt(100) = sqrt(7)/10\r
\n" ); document.write( "\n" ); document.write( "(2.) (sqrt(18) + sqrt(24)) / sqrt(6)\r
\n" ); document.write( "\n" ); document.write( "Multiply numerator and denominator by sqrt(6):
\n" ); document.write( "sqrt(6)*((sqrt(18)+sqrt(24)) / [sqrt(6)*sqrt(6)] =
\n" ); document.write( "[sqrt(6*18) + sqrt(6*24)] / 6 =\r
\n" ); document.write( "\n" ); document.write( "[sqrt(108) + sqrt(144)] / 6 =\r
\n" ); document.write( "\n" ); document.write( "[sqrt(36*3) + 12] / 6 =
\n" ); document.write( "[6*sqrt(3) + 12] / 6 =\r
\n" ); document.write( "\n" ); document.write( "sqrt(3) + 2\r
\n" ); document.write( "\n" ); document.write( "(3.) 8/sqrt(6)\r
\n" ); document.write( "\n" ); document.write( "Again multiply numerator and denominator by sqrt(6):\r
\n" ); document.write( "\n" ); document.write( "8*sqrt(6) / [sqrt(6)*sqrt(6)] =
\n" ); document.write( "8*sqrt(6) / 6 =
\n" ); document.write( "(4/3)*sqrt(6)\r
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