document.write( "Question 31958: I know how 2 do the majority of this problem, but theres 1 part that I get stuck on, so I was wondering if u can help me out wit it?\r
\n" ); document.write( "\n" ); document.write( "x^2 - 6x = 16 (Original problem)\r
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\n" ); document.write( "\n" ); document.write( " x^2 - 6x = 16
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\n" ); document.write( " x^2-6x+(3)^2= 16+(3)^2\r
\n" ); document.write( "\n" ); document.write( " x^2-6x+9= 16+9\r
\n" ); document.write( "\n" ); document.write( " (x-3)^2= 25....Wut comes after this???
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Algebra.Com's Answer #18503 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"+%28x-3%29%5E2+=+25+\"\r
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\n" ); document.write( "\n" ); document.write( "we need to get rid of the squared term. To do that we do the \"opposite\" which is take square root of both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"+%28x-3%29+=+sqrt%2825%29+\" or \"+%28x-3%29+=+-+sqrt%2825%29+\"
\n" ); document.write( "x-3 = 5 or x-3 = -5
\n" ); document.write( "so,
\n" ); document.write( "x = 8 or x = -2\r
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\n" ); document.write( "\n" ); document.write( "jon
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