document.write( "Question 31958: I know how 2 do the majority of this problem, but theres 1 part that I get stuck on, so I was wondering if u can help me out wit it?\r
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document.write( "x^2 - 6x = 16 (Original problem)\r
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document.write( "Solution: \r
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document.write( " x^2 - 6x = 16
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document.write( " x^2-6x+(3)^2= 16+(3)^2\r
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document.write( " x^2-6x+9= 16+9\r
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document.write( " (x-3)^2= 25....Wut comes after this??? \n" );
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Algebra.Com's Answer #18503 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we need to get rid of the squared term. To do that we do the \"opposite\" which is take square root of both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "x-3 = 5 or x-3 = -5 \n" ); document.write( "so, \n" ); document.write( "x = 8 or x = -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon \n" ); document.write( " \n" ); document.write( " |