document.write( "Question 252882: If n < 0, which of the following could be true?\r
\n" ); document.write( "\n" ); document.write( "I. 2n < n^2
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\n" ); document.write( "\n" ); document.write( " (A) None (B) I only (C) I and II only
\n" ); document.write( " (D) I and III only (E) I, II, and III
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Algebra.Com's Answer #185026 by Edwin McCravy(20060) $\"\"$ $\"About$

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document.write( "I.     \r\n" );
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document.write( "is always true if , because if we divided both sides\r\n" );
document.write( "by n, a negative number, the inequality would be reversed \r\n" );
document.write( "and we'd have\r\n" );
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document.write( "      \r\n" );
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document.write( "and 2 is always greater than any negative number n.\r\n" );
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document.write( "II.     \r\n" );
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document.write( "is always true because if we divided both sides by n,\r\n" );
document.write( "which is a negative number, the inequality would be\r\n" );
document.write( "reversed and we'd have \r\n" );
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document.write( "      \r\n" );
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document.write( "and that is always true.\r\n" );
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document.write( "III.   \r\n" );
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document.write( "That's true sometimnes but not always.  If we divided through\r\n" );
document.write( "by n, which is a negative number, the inequality would be\r\n" );
document.write( "reversed and we'd have\r\n" );
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document.write( "        \r\n" );
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document.write( "So that would be true sometimes, like when \r\n" );
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document.write( "       \r\n" );
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document.write( "but would be false, like when \r\n" );
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document.write( "But since the word is \"could be true\" and not\r\n" );
document.write( "\"always true\", we have to include it too,\r\n" );
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document.write( "so the answer is (E) I, II, and III\r\n" );
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document.write( "It it had says \"always\" instead of \"could\" then the\r\n" );
document.write( "answer would have been C.  But since it's \"could\" \r\n" );
document.write( "it's E.\r\n" );
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document.write( "Edwin

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