document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252899>Question 252899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A business is owned by 3 men and 1 women, each of whom has an equal share . If one of the men sells 1/2  of his share to the woman, and another of the men keeps 2/3  of his share and sells the rest to the woman, what fraction of the business will the woman own ?\r<BR>\n" );
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document.write( "(A)  5/24  (B)   11/24   (C)  1/2  (D)  13/24   (E)  11/6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185008 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185008\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The woman starts with 1/4 share & each of the three men start with 1/4 share.<BR>\n" );
document.write( "Thus the woman's share increases by:<BR>\n" );
document.write( "1/4+1/2*1/4+1/3*1/4<BR>\n" );
document.write( "1/4+1/8+1/12 now find a common denominator & add.<BR>\n" );
document.write( "(6+3+2)/24=11/24 is the woman's final shares.<BR>\n" );
document.write( "ANSWER B). </SPAN>\n" );
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