document.write( "Question 252900: When n is divided by 5, the remainder is 4. When n is divided by 4, the remainder is 3. If 0 < n < 100, what is one possible value of n ?
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Algebra.Com's Answer #185006 by Theo(13342)![]() ![]() You can put this solution on YOUR website! When n is divided by 5, the remainder is 4. When n is divided by 4, the remainder is 3. If 0 < n < 100, what is one possible value of n ? \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n/5 = x + 4/5 \n" ); document.write( "n/4 = y + 3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply first equation by 5 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 5x + 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply second equation by 4 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 4y + 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your 2 equations become:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 5x + 4 \n" ); document.write( "n = 4y + 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since both expressions equal to n, then they are equal to each other so you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x + 4 = 4y + 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = (4y-1)/5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if y = 1, then x = 3/5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the assumption is that you want a whole number (integer) so this answer is not good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the numerator was 15, then you would get 15/5 = 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "set your numerator equal to 15 and solve for y to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4y - 1 = 15 \n" ); document.write( "add 1 to both sides to get 4y = 16 \n" ); document.write( "divide both sides by 4 to get y = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if y = 4, then x = 15/5 = 3 which should satisfy the equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get x = 3 and y = 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your two original equations were:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n/5 = x + 4/5 \n" ); document.write( "n/4 = y + 3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substitute 3 for x and 4 for y to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n/5 = 3 + 4/5 \n" ); document.write( "n/4 = 4 + 3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply first equation by 5 and second equation by 4 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 5*3 + 4 \n" ); document.write( "n = 4*4 + 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for n to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 19 \n" ); document.write( "n = 19\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "one of your possible values for n = 19.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "19/5 = 3 with a remainder of 4. \n" ); document.write( "19/4 = 4 with a remainder of 3.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |