document.write( "Question 252881: Three boys have marbles in the ratio 19 : 5 : 3. If the boy with the least number has 9 marbles, how many marbles does the boy with the greatest number have?\r
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document.write( "(A) 57 (B) 62 (C) 48 (D) 54 (E) 70
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Algebra.Com's Answer #185001 by Theo(13342)![]() ![]() You can put this solution on YOUR website! let A be the one with the largest number. \n" ); document.write( "let B be the one with the middle number. \n" ); document.write( "let C be the one with the smallest number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let a = the number of marbles that A has. \n" ); document.write( "let b = the number of marbles that B has. \n" ); document.write( "let c = the number of marbles that C has.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a:b:c = 19:5:3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "C has 9 marbles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9/3 = 3 which means that C has 3 times the marbles as it's ratio number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to keep the ratios intact, all others in the chain have to be multiplied by 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a:b:c = 19:5:3 = 57:15:9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means that A has 57 marbles while B has 15 marbles while C has 9 marbles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can also use the ratio formula to find the correct value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b:c = 5:3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is the same as b/c = 5/3 since a fraction is a ratio of 2 numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have b/c = 5/3. \n" ); document.write( "you know that c = 9. \n" ); document.write( "the equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b/9 = 5/3 \n" ); document.write( "multiply both sides of this equation by 9 to get: \n" ); document.write( "b = (9*5)/3 = 45/3 = 15.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now that you know b, you can solve for a in the same manner.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a:b = 19:5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is the same as a/b = 19/5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have a/b = 19/5. \n" ); document.write( "you know that b is 15. \n" ); document.write( "the equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a/15 = 19/5 \n" ); document.write( "multiply both sides of this equation by 15 to get: \n" ); document.write( "a = (15*19)/5 = 285/5 = 57\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you wind up with:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = 57 \n" ); document.write( "b = 15 \n" ); document.write( "c = 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your question was how many marbles does the boy with the greatest number have?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your answer is selection A (57).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |