document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31921>Question 31921</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having a hard time understanding the step by step process in factor competely. Here are my answer, but I'm still not comfortable with it, please check my work and point out my errors. Greatly apprecated.Thank you \r<BR>\n" );
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document.write( "Factor completely:<BR>\n" );
document.write( "x2 – 5x – 14<BR>\n" );
document.write( "x^2-5x-7\r<BR>\n" );
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document.write( "Factor completely:<BR>\n" );
document.write( "4x2 – 36y2<BR>\n" );
document.write( "=2x^2-18y^2<BR>\n" );
document.write( "=(2x^2- 9y^2)<BR>\n" );
document.write( "=(2x^2-3y^2)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18496 by </B><A HREF=/tutors/aboutme.mpl?userid=benni1013><B>benni1013(206)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=benni1013><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Whoa partner I believe you are way off in left field. Let to talk about so lets get started.\r<BR>\n" );
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document.write( "Your first question: Factor completely: x^2-5x-14<BR>\n" );
document.write( "Fact: A binomial times a binomial equals a trinomial<BR>\n" );
document.write( "Ask yourself what factors of negative 14 equals 5?<BR>\n" );
document.write( "Answer: 7, -2<BR>\n" );
document.write( "So: x^2+7x-2x-14==>x(x+7)-2(x+7)<BR>\n" );
document.write( "The same numbers in the parentheses is one of your quantities the one outside is the other==>(x-2)(x+7)\r<BR>\n" );
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document.write( "Your second question follows under the special rule of \"the difference of two squares\" this occurs when the middle term become zero in multiplying two binomials and the format is: (x-y)(x+y)\r<BR>\n" );
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document.write( "Back to your problem:(2x-6y)(2x+6y) is your answer. </SPAN>\n" );
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