document.write( "Question 31925This question is from textbook pre-algebra
\n" ); document.write( ": can anyone please help with this, 1/5+n=2n-4/5 \n" ); document.write( "
Algebra.Com's Answer #18495 by Fermat(136)\"\" \"About 
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\n" ); document.write( "I'm not usure if your expression is,
\n" ); document.write( "1) (1/5) + n = 2n - (4/5)
\n" ); document.write( "2) 1/(5+n) = (2n-4)/5
\n" ); document.write( "3) (1/5) + n = (2n-4)/5
\n" ); document.write( "4) 1/(5+n) = 2n - (4/5)
\n" ); document.write( "If it's 1), then
\n" ); document.write( "(1/5) + n = 2n - (4/5)
\n" ); document.write( "(1/5) + (4/5) = 2n - n
\n" ); document.write( "5/5 = n
\n" ); document.write( "n = 1
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\n" ); document.write( "If it's 2),
\n" ); document.write( "1/(5+n) = (2n-4)/5
\n" ); document.write( "cross-multiply - i.e. multiply the numerator of the lhs by denominator of the rhs and multiply the numerator of the rhs by the denominator of the lhs. This gives,
\n" ); document.write( "1*(5) = (2n-4)*(5+n)
\n" ); document.write( "5 = 10n + 2nē - 20 - 4n
\n" ); document.write( "2nē + 6n - 25 = 0
\n" ); document.write( "using the quadratic formula, \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\", we get
\n" ); document.write( "\"n+=+%28-6+%2B-+sqrt%28+6%5E2-4%2A2%2A%28-25%29+%29%29%2F%282%2A2%29+\"
\n" ); document.write( "\"n+=+%28-6+%2B-+sqrt%28+36%2B200+%29%29%2F%284%29+\"
\n" ); document.write( "\"n+=+%28-6+%2B-+15.3623%29%2F%284%29+\"
\n" ); document.write( "n = 2.3406, n = -5.3406
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\n" ); document.write( "If it's 3) or 4), could you get the answer to those ?
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