document.write( "Question 252819: Please help in answering this question.\r
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document.write( "The quality assurance engineer of a television manufacturer inspects TVs in lots of 100. He selects 5 of the 100 TVs at random and inspects them thoroughly. Assuming that 6 ofte 100 TVs in the current lot are defective, find the probability that the number of defective TVs obtained by the engineer is
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document.write( "a. exactly one
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document.write( "b. at most one
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document.write( "c. at least one \n" );
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Algebra.Com's Answer #184933 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Please help in answering this question. \n" ); document.write( "The quality assurance engineer of a television manufacturer inspects TVs in lots of 100. He selects 5 of the 100 TVs at random and inspects them thoroughly. \n" ); document.write( "---- \n" ); document.write( "Binomial: n = 5 ; p = 0.06 ; x varies \n" ); document.write( "------ \n" ); document.write( " Assuming that 6 of the 100 TVs the current lot are defective, find the probability that the number of defective TVs obtained by the engineer is \n" ); document.write( "a. exactly one \n" ); document.write( "P(x=1) = 5C1(0.06)(0.94)^4 = 0.2342 \n" ); document.write( "-------------------------------- \n" ); document.write( "b. at most one \n" ); document.write( "P(x=0 or 1) = 0.7339 + 0.2342 = 0.9681 \n" ); document.write( "---------------------------------- \n" ); document.write( "c. at least one \n" ); document.write( "P(x>=1) = 1- P(x=0) \n" ); document.write( "1 - 5C0(0.06)^0*(0.94)^5 \n" ); document.write( "= 1 - 1*1*(0.94)^5 \n" ); document.write( "= 1 - 0.7339 \n" ); document.write( "= 0.2661 \n" ); document.write( "---------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |