document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250626>Question 250626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> WHAT IS THE 10TH TERM OF THE GEOMETRIC SEQUENCE 64,-32,16,8??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184815 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184815\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given Geometric sequence is 64,-32,16,-8,4,...<BR>\n" );
document.write( "       The first term   a = 64<BR>\n" );
document.write( "       The common ratio r = -1/2 <BR>\n" );
document.write( "       The nth tern    Tn = ar^(n-1)<BR>\n" );
document.write( "                       Tn = 64*(-1/2)^(n-1)<BR>\n" );
document.write( "Put n=10.<BR>\n" );
document.write( "       The 10th term   T10 = 64*(-1/2)^(10-1)<BR>\n" );
document.write( "                           = 64*(-1/2)^9<BR>\n" );
document.write( "                           = -(2^6)/2^9<BR>\n" );
document.write( "                           = -1/2^3<BR>\n" );
document.write( "                           = -1/8        <BR>\n" );
document.write( "                         </SPAN>\n" );
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