document.write( "Question 250620: solve the equation in the interval [0,2Pi). sin(pi-x)=1 \n" ); document.write( "
Algebra.Com's Answer #184814 by drk(1908)\"\" \"About 
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We start with
\n" ); document.write( "\"sin%28pi-X%29+=+1\".
\n" ); document.write( "Here is one way. Replace (pi-X) with A.
\n" ); document.write( "We have
\n" ); document.write( "\"Sin%28A%29+=+1\".
\n" ); document.write( "At what values of A is the sin = 1?
\n" ); document.write( "\"A+=+pi%2F2\" only.
\n" ); document.write( "Substitute (pi-X) back for A and we get
\n" ); document.write( "\"PI-X+=+pi%2F2\".
\n" ); document.write( "Solving for X, we get
\n" ); document.write( "\"X+=+pi%2F2\".
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