document.write( "Question 250720: A chemist has one solution that is 20% saline and a second that is 65% saline. How many gallons of each should be mixed to get 120 gallons of a solution which is 50% saline? \n" ); document.write( "
Algebra.Com's Answer #184778 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! This is a mixture problem. Here is the table: \n" ); document.write( "SALINE . . . . . % . . . . . .gal . . . . . .%gal \n" ); document.write( "A . .. . . . . . .. 20 . . . .. . G . . . . . . . 20G \n" ); document.write( "B . . . . . . . . .. 65 . . . . .120-G . . . .7800 - 65G \n" ); document.write( "mix . . . . . . . 50 . . . . . .120 . . . . . .6000. \n" ); document.write( "-- \n" ); document.write( "I put in all information from the problem and then I had to use variables. I let G = gallons of A and 120-G be gallons of B. It is always total gallons - X.\r \n" ); document.write( "\n" ); document.write( "Now, \n" ); document.write( "20G + 7800 - 65G = 6000 \n" ); document.write( "-45G = -1800 \n" ); document.write( "G = 40. \n" ); document.write( "I need 40 gallons of the 20% saline solution and 80 gallons of 65% saline solution. \n" ); document.write( " |