document.write( "Question 252709: Trying to develop a linear equation for:\r
\n" ); document.write( "\n" ); document.write( "Gas used: 5, 8, 12, 15, 18, 20, 22, 25
\n" ); document.write( "Miles driven, 80, 100, 180, 225, 280, 290, 320, 375
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Algebra.Com's Answer #184762 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
We have the following table:
\n" ); document.write( "Gas used: 5, 8, 12, 15, 18, 20, 22, 25
\n" ); document.write( "Miles driven, 80, 100, 180, 225, 280, 290, 320, 375.\r
\n" ); document.write( "\n" ); document.write( "To create a linear model, we want to apply some rule to x and then get y.
\n" ); document.write( "Notice
\n" ); document.write( "5*15 = 75 + 5 = 80
\n" ); document.write( "8*15 = 120 - 20 = 100
\n" ); document.write( "12*15 = 180
\n" ); document.write( "15*15 = 225
\n" ); document.write( "18*15 = 270 + 10 = 280
\n" ); document.write( "20*15 = 300 - 10 = 290
\n" ); document.write( "22*15 = 330 - 10 = 320
\n" ); document.write( "25*15 = 375.\r
\n" ); document.write( "\n" ); document.write( "We can't create a perfect linear model, but this means we have a \"regression\" model, or an equation that gets us close:
\n" ); document.write( "M = 15G.
\n" ); document.write( "Hope this helps.
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