document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250702>Question 250702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is -64. Twice the first number is 1 more than the second. Find the two numbers<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184743 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X = first number and Y = second number.<BR>\n" );
document.write( "The sum of two numbers is -64 can be translated as<BR>\n" );
document.write( "(i) X + Y = -64<BR>\n" );
document.write( "Twice the first number is 1 more than the second can be translated as<BR>\n" );
document.write( "(ii) 2X = Y + 1.<BR>\n" );
document.write( "We can use substitution to solve. Solve the (ii) for Y. We get<BR>\n" );
document.write( "(iii) Y = 2X - 1<BR>\n" );
document.write( "Substitute (iii) into (i) to get<BR>\n" );
document.write( "(iv) X + 2X - 1 = -64<BR>\n" );
document.write( "Solve for X.<BR>\n" );
document.write( "3X - 1 = -64<BR>\n" );
document.write( "3X = -63<BR>\n" );
document.write( "X = -21<BR>\n" );
document.write( "Find Y.<BR>\n" );
document.write( "Y = -43.<BR>\n" );
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