document.write( "Question 252673: 3% of total bulbs are defective from past records.find the probability that the number of defective bulbs are 0 or 1 or 2 or 3 or 4 or 5 if the total number of bulbs are 100 \n" ); document.write( "
Algebra.Com's Answer #184707 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
3% of total bulbs are defective from past records.find the probability that the number of defective bulbs are 0 or 1 or 2 or 3 or 4 or 5 if the total number of bulbs are 100
\n" ); document.write( "------------
\n" ); document.write( "Use the binomial formla for 100 trials with p = 0.03 and x = 0,
\n" ); document.write( "then x = 1, then x = ........and x=5 :
\n" ); document.write( "P(x=k) = nCk*p^k*q(n-k)
\n" ); document.write( "Ex:
\n" ); document.write( "P(x= 2) = 100C2*(0.03)^2*0.97^8 = 0.2252..
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );