document.write( "Question 252650: Working together Deng and Ddolly can sew a set of uniform in 2 hours. If Dolly can do it alone in 5 hours, howw long will it take Deng to do it by herslf? \n" ); document.write( "
Algebra.Com's Answer #184706 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of time it takes Deng working alone \n" ); document.write( "Then Deng works at the rate of 1/x uniform/hr\r \n" ); document.write( "\n" ); document.write( "Deng and Dolly together work at the rate of 1/2 uniform/hour \n" ); document.write( "Dolly, working alone, works at the rate of 1/5 uniform/hr\r \n" ); document.write( "\n" ); document.write( "So, our equation to solve is: \n" ); document.write( "1/x + 1/5= 1/2 multiply each term by 10x \n" ); document.write( "10+2x=5x subtract 2x from each side \n" ); document.write( "10+2x-2x=5x-2x \n" ); document.write( "3x=10 \n" ); document.write( "x=3 1/3 hours=10/3 hours----Amount of time needed for Deng to do the job working alone\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "1/5 +(1/10/3)=1/2 \n" ); document.write( "1/5 +3/10=1/2 \n" ); document.write( "2/10+3/10=1/2 \n" ); document.write( "1/2=1/2\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |