document.write( "Question 252650: Working together Deng and Ddolly can sew a set of uniform in 2 hours. If Dolly can do it alone in 5 hours, howw long will it take Deng to do it by herslf? \n" ); document.write( "
Algebra.Com's Answer #184706 by ptaylor(2198)\"\" \"About 
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Let x=amount of time it takes Deng working alone
\n" ); document.write( "Then Deng works at the rate of 1/x uniform/hr\r
\n" ); document.write( "\n" ); document.write( "Deng and Dolly together work at the rate of 1/2 uniform/hour
\n" ); document.write( "Dolly, working alone, works at the rate of 1/5 uniform/hr\r
\n" ); document.write( "\n" ); document.write( "So, our equation to solve is:
\n" ); document.write( "1/x + 1/5= 1/2 multiply each term by 10x
\n" ); document.write( "10+2x=5x subtract 2x from each side
\n" ); document.write( "10+2x-2x=5x-2x
\n" ); document.write( "3x=10
\n" ); document.write( "x=3 1/3 hours=10/3 hours----Amount of time needed for Deng to do the job working alone\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "1/5 +(1/10/3)=1/2
\n" ); document.write( "1/5 +3/10=1/2
\n" ); document.write( "2/10+3/10=1/2
\n" ); document.write( "1/2=1/2\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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