document.write( "Question 31884: John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be?\r
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document.write( "I aslo get 50 x100 dont think that is correct? Please help \n" );
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Algebra.Com's Answer #18466 by mbarugel(146)![]() ![]() ![]() You can put this solution on YOUR website! Hello! \n" ); document.write( "I've already answered a very similar question, you can see how to work it here.\r \n" ); document.write( "\n" ); document.write( "Using the procedure explained there, the correct answer in your case is that the rectangle should be 75 x 75 (a square)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I hope this helps! \n" ); document.write( "Get more answers at Online Math Answers.com!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |