document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252633>Question 252633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Gideon is 30 years younger than his father, His mother is three times as old as her son. Find Gideon's age if his father is two years older than his mother. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184656 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let G = Gideon M = mother, and F = father.<BR>\n" );
document.write( "(i)  G = F - 30.<BR>\n" );
document.write( "(ii) M = 3G<BR>\n" );
document.write( "(iii)F = M + 2.<BR>\n" );
document.write( "Substitute (iii) into (i) to get<BR>\n" );
document.write( "(iv) G = M + 2 - 30<BR>\n" );
document.write( "(ii) M = 3G<BR>\n" );
document.write( "Substitute (ii) into (iv) to get<BR>\n" );
document.write( "(v) G = 3G + 2 - 30.<BR>\n" );
document.write( "Solve for G.<BR>\n" );
document.write( "-2G = -28<BR>\n" );
document.write( "G = 14.<BR>\n" );
document.write( "M = 42.<BR>\n" );
document.write( "F = 44.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );