document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252635>Question 252635</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A 400 gram solution made up of 40% sugar must be added to a 200 gram solution. What should be the percentage of sugar in 200gram of solution in order to produce a 38% sugar solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184655 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is your traditional mixture problem. Let's create the table:\r<BR>\n" );
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document.write( "sugar . . . % . . . gram . . . %gram<BR>\n" );
document.write( "A . . . . . 40 . . .400 . . . . 16000<BR>\n" );
document.write( "B . . . . . X . . . 200 . . . . 200X<BR>\n" );
document.write( "MIX . . . . 38 . . .600 . . . . 22800.\r<BR>\n" );
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document.write( "I put in the 40% and 400 grams for first sugar as well as the 200 grams for the second sugar. I didn't know % of second sugar, so I call it X. The mixture calls for 38%, so I put it in the mix, % box. 400 grams + 200 grams = 600 grams - the total number of grams in the mix. <BR>\n" );
document.write( "% x gram = %gram.<BR>\n" );
document.write( "Now,<BR>\n" );
document.write( "16000 + 200X = 22800.<BR>\n" );
document.write( "200X = 6800<BR>\n" );
document.write( "X = 34%.<BR>\n" );
document.write( "So, we need 34% of the 200 gram sugar.<BR>\n" );
document.write( " </SPAN>\n" );
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