document.write( "Question 252615: its a word problem :
\n" ); document.write( "michelle is 5 years younger than cindy . janet is ten years less than twice of cindy age . kenny is 10 years old . the ratio of janets age equal s the ratio of michelles age to kenny's age . how old are cindy , janet, and michelle ? \n" ); document.write( "
Algebra.Com's Answer #184634 by palanisamy(496)\"\" \"About 
You can put this solution on YOUR website!
The age of Kenny = 10
\n" ); document.write( "Let the age of Cindy be x
\n" ); document.write( "Janet is ten years less than twice of cindy age
\n" ); document.write( "The the age of Janet = 2x-10
\n" ); document.write( "Michelle is 5 years younger than cindy
\n" ); document.write( "The the age of Michelle = x-5
\n" ); document.write( "Given, the ratio of janets age equal s the ratio of michelles age to kenny's age
\n" ); document.write( " 2x-10 = (x-5)/10
\n" ); document.write( " 20x-100 = x-5
\n" ); document.write( " 20x-x = 100-5
\n" ); document.write( " 19x = 95
\n" ); document.write( " x = 95/19
\n" ); document.write( " x = 5
\n" ); document.write( "Therefore the age of Cindy = 5
\n" ); document.write( " the age of Janet = 2*5-10 = 0
\n" ); document.write( " the age of Michelle= x-5 = 5-5 = 0
\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );