document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250799>Question 250799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account?\r<BR>\n" );
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document.write( "A) $1,500 at 2%; $2,300 at 4%<BR>\n" );
document.write( "B) $1,400 at 2%; $2,200 at 4%<BR>\n" );
document.write( "C) $1,000 at 2%; $1,800 at 4%<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184632 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the man invest an amount x at 2% interest.<BR>\n" );
document.write( "Then, he invests an amount (x+800) at 4% interest.<BR>\n" );
document.write( "Total simple interest for one year is<BR>\n" );
document.write( "   x*2/100 + (x+800)*4/100 = 92<BR>\n" );
document.write( "     2x+4x+3200 = 9200<BR>\n" );
document.write( "             6x = 9200-3200<BR>\n" );
document.write( "             6x = 6000<BR>\n" );
document.write( "              x = 1000<BR>\n" );
document.write( "So the man invested $ 1000 at 2% interest and $ 1800 at 4% interest.<BR>\n" );
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